W18x46 Beam Capacity: Concentrated Load, 16ft Span, A992 Steel
Published on September 12, 2024
Question
A 16ft W18×46 beam of a A992 steel with lateral support at the compression flange at end supports only. A concentrated service liveload is applied 4ft from the left support. The bearimg length at the support is 4 inches and 8 inches at the concentrated load. The thickness of each bearing plate is 3/4 inch. Determine the maximum concentrated liveload that the beam may carry considering bending, shear, web crippling, and local web yielding. Neglect beam weight in all calculations.
Answer
Problem Statement:
Determine the maximum concentrated live load a W18×46 A992 steel beam can carry, considering bending, shear, web crippling, and local web yielding, given the following:
- Beam: W18×46, A992 steel
- Span: 16 ft (simply supported with lateral support at compression flange at ends only)
- Load: Concentrated service live load
- Load Location: 4 ft from the left support
- Bearing Length at Supports: 4 inches
- Bearing Length at Load: 8 inches
- Bearing Plate Thickness: 3/4 inch
- Neglect beam weight
Solution:
We will analyze each failure mode separately and find the minimum load capacity, which will govern the design.
1. Bending Capacity:
-
Moment Calculation:
- The maximum moment due to a concentrated load on a simply supported beam occurs at the load point.
- Using the formula for the moment at a point load on a simply supported beam:
-
- where:
- P = Concentrated load
- a = Distance from left support to load = 4 ft
- b = Distance from right support to load = 12 ft
- L = Span of the beam = 16 ft
-
ft-kips
-
-
Section Modulus:
- Look up the section modulus (
) for a W18×46 beam in the AISC Steel Construction Manual. - For a W18x46,
- Look up the section modulus (
-
Nominal Flexural Strength (M_n):
-
- where:
-
= Yield strength of A992 steel = 50 ksi
-
-
-
-
Design Flexural Strength (φM_n):
-
= 0.9 (for flexure) -
-
-
Maximum Load Capacity (P_bending):
- Equate the maximum moment due to the load to the design flexural strength:
-
-
2. Shear Capacity:
-
Shear Force Calculation:
- The maximum shear force in a simply supported beam with a concentrated load occurs at the support closer to the load.
-
kips
-
Nominal Shear Strength (V_n):
-
- where:
-
= Area of the web = - d = Depth of the beam (from AISC manual) = 18.0 in
-
= Web thickness (from AISC manual) = 0.415 in -
= Shear coefficient (from AISC manual, typically 1.0 for beams without stiffeners)
-
-
-
-
Design Shear Strength (φV_n):
-
= 1.0 (for shear) -
-
-
Maximum Load Capacity (P_shear):
- Equate the maximum shear force due to the load to the design shear strength:
-
-
3. Web Crippling:
-
Bearing Strength at Support:
- Check the web crippling at the support with the smaller bearing length (4 inches).
-
- where:
- N = Bearing length at support = 4 in
-
= Flange thickness (from AISC manual) = 0.695 in
-
-
Design Bearing Strength at Support (φR_n):
-
= 0.75 (for web crippling) -
-
-
Maximum Load Capacity at Support (P_crippling_support):
- Since the reaction at each support is half the total load:
-
-
Bearing Strength at Load Point:
- Repeat the above calculations for the bearing length at the load point (8 inches).
- You’ll find that the bearing strength at the load point is significantly higher than at the support, so it won’t govern the design.
4. Local Web Yielding:
-
Bearing Yield Strength:
-
-
Design Bearing Yield Strength (φR_n):
-
= 1.0 (for local yielding) -
-
-
Maximum Load Capacity at Support (P_yielding_support):
- Since the reaction at each support is half the total load:
-
5. Governing Load:
Comparing the maximum load capacities calculated for each failure mode:
The lowest value is
.
Conclusion:
The maximum concentrated live load that the W18×46 A992 steel beam can carry, considering all the specified failure modes, is 97.63 kips. The governing failure mode is bending.