Find the smallest possible values of A and B for the number 645A2879B8 to be divisible by both 8 and 9.

Published on November 11, 2024

To find the smallest possible values for A and B in a 10-digit number divisible by both 8 and 9, the last three digits (9B8) must be divisible by 8, and the sum of all digits must be divisible by 9. This leads to B=2 and A=3 as the smallest possible values.

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